Final Answer:
(a) The minimum chemical energy required to generate each photon of 550 nm light is approximately **2.25 eV.**
(b) To produce one photon of 550 nm light, the minimum number of ATP molecules needed is approximately **7.5 ATP molecules.**
(c) In the flash lasting 100 ms with a power of 1.2 mW, approximately **7.2 x
hotons** are emitted.
Step-by-step explanation:
(a) The energy of a photon can be calculated using the formula
is Planck's constant,
is the speed of light, and
is the wavelength. Substituting the values, the energy of a 550 nm photon is approximately 2.25 eV.
(b) To determine the number of ATP molecules needed, the total energy required is divided by the energy provided by one ATP molecule.
Substituting the values, approximately 7.5 ATP molecules are needed.
(c) The total number of photons emitted can be calculated using the formula
Rearranging the formula to solve for energy emitted, and then dividing by the energy of one photon, we find the total number of photons. Substituting the values, approximately
photons are emitted in the flash.
In summary, the chemi-luminescence process in fireflies requires a minimum energy of 2.25 eV per photon, and to produce one photon of 550 nm light, around 7.5 ATP molecules are needed. In a flash lasting 100 ms with a power of 1.2 mW, approximately
photons are emitted.