Question

An allele W, for white wool, is dominant over allele w, for black wool. In a sample of 900 sheep, 891 are white and 9 are black. Calculate the allele frequencies within this population, assuming that the population is in H-W equilibrium.

a. Recessive allele frequency is 10% and the dominant allele frequency is 90%
b. Recessive allele frequency is 20% and the dominant allele frequency is 60%
c. Recessive allele frequency is 90% and the dominant allele frequency is 10%
d. Recessive allele frequency is 25% and the dominant allele frequency is 75%

Answer 1

To calculate the allele frequencies within a population of flowers in Hardy-Weinberg equilibrium, we can use the equation p^2 + 2pq + q^2 = 1. In this case, the dominant allele frequency (A) is 0.875 and the recessive allele frequency (a) is 0.125.

Step-by-step explanation:

The question is asking for the allele frequencies within a population of flowers, assuming that the population is in Hardy-Weinberg equilibrium. To calculate the allele frequencies, we can use the Hardy-Weinberg equation, which states that the frequency of the dominant allele (p) squared plus two times the frequency of the dominant allele (p) times the frequency of the recessive allele (q) plus the frequency of the recessive allele (q) squared is equal to 1.

In this case, we have 600 blue flowers and 200 red flowers. Let's assume blue flower color is dominant (AA or Aa) and red flower color is recessive (aa). We can calculate the frequencies as follows:

1. Blue flower frequency = (600 + 0.5 * 200) / 800 = 0.875
2. Red flower frequency = (0.5 * 200) / 800 = 0.125

So, the expected allele frequencies for flower color in this population are:

1. Dominant allele frequency (A) = 0.875
2. Recessive allele frequency (a) = 0.125