Final answer:
The frequency of the yellow allele (w) in the population is 0.3, calculated by taking the square root of the proportion of yellow kernels (ww) in the sample, which represents q² in the Hardy-Weinberg equilibrium.
Step-by-step explanation:
To calculate the frequency of the yellow allele (w) in kernels of corn, given that 9 out of 100 kernels are yellow (ww) and the population is in Hardy-Weinberg equilibrium, we need to use the Hardy-Weinberg principle. The frequency of the homozygous recessive genotype (ww) is the square of the frequency of the recessive allele (w), represented as q². From the sample, we have 9 yellow kernels, so q² = 9/100 = 0.09. To find the frequency of the recessive allele (q), we take the square root of q², which gives us q = √0.09. This simplifies to q = 0.3, so the frequency of the yellow allele (w) in the population is 0.3.