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Given that a particular photon has a frequency of 7.85 x 10^15 Hz. Using Planck's constant (h= 6.626 x 10^-34 J x s), calculate the photon's energy.

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Final answer:

The energy of a photon with a frequency of 7.85 x 10^15 Hz is calculated using the formula E = hf, resulting in an energy of 5.2011 x 10^-18 joules.

Step-by-step explanation:

To calculate the energy of a photon with a given frequency, we can use the formula E = hf, where E is the energy of the photon, h is Planck's constant, and f is the frequency of the photon.

In this case, the frequency (f) is 7.85 x 1015 Hz, and Planck's constant (h) is 6.626 x 10-34 J x s.

Using the formula, the energy E of the photon is calculated as follows:

E = (6.626 x 10-34 J x s) x (7.85 x 1015 Hz)

We multiply Planck's constant by the frequency to find that:

E = 5.2011 x 10-18 joules

Therefore, the energy of the photon with a frequency of 7.85 x 1015 Hz is 5.2011 x 10-18 joules.

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