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For the polynomial below, - 1 is a zero. f(x) = x3 - 5x2 - 2x 4 Express f(x) as a product of linear factors.

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f(x) as a product of linear factors is determined as f(x) = (x + 1)(x² - 6x + 4).

How to calculate the linear factor of the polynomial?

The factors of the polynomial is calculated as follows;

The given polynomial function;

f(x) = x³ - 5x² - 2x + 4

The zero of the polynomial function is - 1, so a factor of the polynomial becomes;

x = - 1

x + 1 = 0

factor = (x + 1)

The other factors of the polynomial is calculated as follows;

x² - 6x + 4

---------------------------------

x + 1 | (x³ - 5x² - 2x + 4)

- (x³ + x²)

--------------------------------

-6x² - 2x + 4

- (-6x² - 6x)

-----------------------------------

4x + 4

- (4x + 4)

----------------------------

0

We cannot factorize the quotient (x² - 6x + 4) further, so the linear factor of the polynomial becomes;

f(x) = (x + 1)(x² - 6x + 4)

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