Final answer:
The mass of the SF4 sample containing 1.825×10^24 fluorine atoms is calculated as 81.89 grams, by first finding the number of moles of SF4 and then multiplying it by the molar mass of SF4.
Step-by-step explanation:
To determine the mass of a sample of SF4 that contains 1.825×1024 fluorine atoms, we first need to find the number of moles of SF4 in the sample.
Since one molecule of SF4 has four fluorine atoms, we divide the total number of fluorine atoms by four to get the number of SF4 molecules.
Number of SF4 molecules = 1.825×1024 atoms F / 4 atoms F per molecule
= 4.5625×1023 molecules SF4
To convert the number of molecules to moles, we use Avogadro's number, which is approximately 6.022×1023 molecules/mole.
Moles of SF4 = 4.5625×1023 molecules / 6.022×1023 molecules/mole
= 0.7578 moles SF4
Next, we calculate the molar mass of SF4. The molar mass of sulfur (S) is approximately 32.07 g/mole, and the molar mass of fluorine (F) is about 19.00 g/mole.
Molar mass of SF4 = 32.07 g/mole + 4(19.00 g/mole)
= 108.07 g/mole
Finally, we multiply the molar mass of SF4 by the number of moles to find the mass of the sample.
Mass of SF4 = 0.7578 moles × 108.07 g/mole
= 81.89 grams
Therefore, the mass of the SF4 sample is 81.89 grams.