Answer:
We have, block size = 512
number of block numbers in an indirection block
= block size / 4
= 128
number of blocks for file data in that file object
= 16 + 128 + 128^2 + 128^3
Maximum file size:
(direct + single indirect + double indirect + triple indirect) * (blocksize)
= (16 + 512/4 + (512/4)^2 + (512/4)^3) * (512)
= 68853964800 bytes, ~64 gigs
Step-by-step explanation: