Step-by-step explanation:
this question we need to find the amount of heat they just removed from 60 g of steam At 100°C. To change too 60 g of water two 20 degrees Celsius. The specific heat of liquid water As 4.184 jewel program degree Celsius specific heat of steam As 1.84 joules per gram degree C. Heat off vaporization of water to is 40.67. Kill a jewel family. First this 60 g of 18 has converted to 60 g of water at 100°C. As the heat removed will be en indu L status and as the number of malls and Elysa heat of vaporization, that is 40.67. Hello Joel palmer so that each one that is the heat removed is equal to 60 indu 40.65 divided by 18. That is the given Mars by Moller mass gives the number of moles. That is by 16 to 40.65 by 18. Such that H one. The heat remote is obtained us 1 35.5 kg jule. Now the water is converted from 100°C to 20 degrees Celsius. The heat at a more can be calculated by mm indu C'e, hindu deity. That is M is the mass. C is the specific heat capacity. That is 4.18 Joule per kilogram and DT is the change in temperature that is 100 minus 20. That is 80°C says that he'd removed H2 is equal to .06 Hindu 4.18. For in due 100 minus 20 obtained us 20 kg jokes. Thus the total heat. Little mood will be H one Plus H two. That is 1 35.5 plus 20 And it has obtained as 155.5 kilo jule.