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39 votes
39 votes
Solve the equation
2x^3-4x^2-96x=-8x^2

User TheBestBigAl
by
2.6k points

1 Answer

5 votes
5 votes

Answer:

x = 6 or x = 0 or x = -8

Explanation:

Solve for x over the real numbers:

2 x^3 - 4 x^2 - 96 x = -8 x^2

Add 8 x^2 to both sides:

2 x^3 + 4 x^2 - 96 x = 0

The left-hand side factors into a product with four terms:

2 x (x - 6) (x + 8) = 0

Divide both sides by 2:

x (x - 6) (x + 8) = 0

Split into three equations:

x - 6 = 0 or x = 0 or x + 8 = 0

Add 6 to both sides:

x = 6 or x = 0 or x + 8 = 0

Subtract 8 from both sides:

Answer: x = 6 or x = 0 or x = -8

User Tyler McMaster
by
2.6k points