Question

3.

8.6.2.8
Triangle ABC has
vertices A (0, -4), B (5,
-4) and C (5,8). What
Is the length, in units,
of AC.

Answer 1

9514 1404 393

Answer:

13 units

Explanation:

The distance formula is useful for this.

d = √((x2 -x1)² +(y2 -y1)²)

d = √((5 -0)² +(8 -(-4))²) = √(25 +144) = √169

d = 13

The length of AC is 13 units.