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Please do this I have to turn it in to pass

Please do this I have to turn it in to pass-example-1
User Musabbir Arrafi
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1 Answer

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15 votes

Answer:

I've solved all of the above for you :)

Explanation:

3q² + 7 = 55

3q² = + 7 - 7 = 55 - 7

3q² = 48

3q²/3 = 48/3

q² = 12

q = 23

√p - 4 = - 5

p - 4 = (-5)²

p - 4 + 4 = 25 + 4

p = 29

5√a/2 = 40

5√a/2 × 2 = 40 × 2

5√a = 80

5√a/5 = 80/5

√a = 16

a = 256

c³ - 4 = 23

c³ - 4 + 4 = 23 + 4

c³ = 27

c = 3

(k + 3)² = 4

k² + 6k + 9 = 4

k² + 6k + 9 - 4 = 0

k² + 6k + 5 = 0

k² + k + 5k + 5 = 0

k(k + 1) + 5(k + 1) = 0

(k + 5) (k + 1) = 0

k = (-5) or (-1)

√s + 4 = 6

s + 4 = (6)²

s + 4 - 4 = 36 - 4

s = 32

(√f - 5) = (√7 - f)

(√f - 5)² = (√7 - f)²

f - 5 = 7 - f

f - 5 + 5 + f = 7 + 5 - f + f

2f/2 = 12/2

f = 6

∛j + 9 = 0

∛j + 9 - 9 = -9

∛j = (-9)

j = (-9)³

j = (-729)

b² - 1 = 24

b² - 1 + 1 = 24 + 1

b² = 25

√b² = √25

b = 5

13 = (w - 2)² + 5

13 = w² - 4w + 4 + 5

13 - 9 = w² - 4w

w² - 4w = 4

w² - 4w - 4 = 0

w² - 2w - 2w - 4 = 0

w(w - 2) - 2(w - 2) = 0

(w - 2) (w - 2) = 0

w = 2 or 2

12 = 4√2x + 1

12/4 = 4√2x + 1/4

3 = √2x + 1

√2x + 1 = 3

2x + 1 = 9

2x + 1 - 1 = 9 - 1

2x/2 = 8/2

x = 4

(g + 1)³ = (-8)

g³ + 1³ + 3g(g + 1) = (-8)

g³ + 1 + 3g² + 3g = (-8)

g³ + 3g² + 3g = (-8) - 1

g³ + 3g² + 3g = -9

g³ + 3g² + 3g + 9 = 0

g = (-3)

∜(5m + 1) = 4

[∜(5m + 1)]⁴ = (4)⁴

5m + 1 = 256

5m + 1 - 1 = 256 - 1

5m/5 = 255/5

m = 51

∛(y³ - 19) = 2

(y³ - 19) = (2)³

y³ - 19 = 8

y³ - 19 + 19 = 8 + 19

y³ = 27

y = 3

User Marcel Overdijk
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