Final answer:
When the concentration of H+ ions in pure water is increased tenfold, the OH- concentration can be found by using the ion product of water, resulting in a new OH- concentration of 1.0 × 10^-8 M, which is option 4.
Step-by-step explanation:
If the concentration of H+ ions is increased to ten times the original concentration in pure water, the new concentration of H+ would become 1.0 × 10-6 M. Since the product of concentrations of H+ and OH- ions must always equal 1.0 × 10-14 at 25 °C, we can determine the new OH- concentration.
[H+] × [OH-] = 1.0 × 10-14
1.0 × 10-6 M × [OH-] = 1.0 × 10-14
[OH-] = ç(1.0 × 10-14 / 1.0 × 10-6) = 1.0 × 10-8 M
Therefore, the resulting OH- concentration of the solution is 1.0 × 10-8 M, which corresponds to option 4 in the given choices.