Final answer:
The total recombinant combinations (TRC) for the genotype AABbCcDD, which has two heterozygous allele pairs (Bb and Cc), would provide 4 possible gamete combinations. Since the calculation excludes sex chromosomes, the TRC would be the same for both males and females with this genotype.
Step-by-step explanation:
The question pertains to the total number of possible gamete combinations, or the total recombinant combinations (TRC), that can be produced by an individual with a particular genotype, specifically AABbCcDD for a male or a female. To determine the TRC for the genotype AABbCcDD, we look at the heterozygous pairs of alleles, as only heterozygous alleles contribute to different gametes through meiosis. Here, the individual has one heterozygous pair at the B locus (Bb), one at the C locus (Cc), and all others are homozygous. Using the forked-line method or Punnett squares, we can see that the individual can produce 2 different types of gametes from the B locus (B or b) and 2 from the C locus (C or c), while the A and D loci will always contribute the same alleles since they are homozygous (AA and DD respectively).
To find the TRC, you multiply the number of variations each heterozygous allele pair can provide, which in this case is 2 (from Bb) multiplied by 2 (from Cc), yielding 4 possible gamete combinations. Since the AABbCcDD genotype does not include sex chromosomes and the TRC calculation depends only on autosomes (non-sex chromosomes), the TRC of 4 applies to both males and females with this genotype.