Final answer:
The probability that the first child will be a roller is 1/2 or 50%.
Step-by-step explanation:
The ability to roll the tongue is determined by a dominant allele. In this case, the woman is a 'roller' but one of her parents is not. The woman's genotype is likely heterozygous (Rr), with the dominant allele for rolling (R) and the recessive allele for non-rolling (r). The man is a nonroller and his genotype is likely homozygous recessive (rr). When we cross these genotypes, the Punnett square predicts that there is a 50% chance (or 1/2 probability) of their first child being a roller with the genotype Rr.