Final answer:
It is true that in a 2's complement integer representation there are more negative numbers than positive, due to the way the most significant bit is used to represent the sign, resulting in an extra negative number for a given number of bits.
Step-by-step explanation:
The assertion that a 2's complement integer representation includes more negative numbers than it does positive ones is true. In a 2's complement system, integers are represented in a binary format, where the most significant bit defines the sign of the number: 0 for positive and 1 for negative. Given a fixed number of bits, say n, there is one more negative number representable than positive numbers. This is because the range of representable numbers is from -2(n-1) to 2(n-1) - 1. For example, with 8 bits, the range is from -128 to +127, including an extra negative number (-128) that does not have a corresponding positive counterpart.