Question

Y + 3 = (x - 6)

“Identify the slope and a point on a line, then graph the line”

How would I graph it with no slope and only one point?

Answer 1

see attached

Explanation:

Given the equation for a line, y +3 = (x -6), you want to identify the slope and a point on the line, then graph it.

Point-slope form

The point-slope form of the equation for a line is ...

y -k = m(x -h) . . . . . . . . line with slope m through point (h, k)

Comparing this to the given equation, you can see ...

• k = -3
• m = 1 . . . . . . . . . . a coefficient of 1 is often "missing" or "implied"
• h = 6

This tells you the slope is 1 and a point on the line is (6, -3).

Graph

You graph this equation by plotting point (6, -3) and drawing a line through it that goes up 1 unit for each 1 unit to the right. A graph is attached.

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Additional comment

If you like, you can rearrange the equation to slope-intercept form by subtracting 3:

y +3 -3 = (x -6) -3

y = x -9

This tells you another point is -9 on the y-axis.