151k views
2 votes
A huge cannon is assembled on an airless planet. The planet has a radius of 5.0×106m and a mass of 2.6×1024kg . The cannon fires a projectile straight up at 3600 m/s .

User JZF
by
7.7k points

1 Answer

4 votes

The height the projectile reach above the surface, given that it was projected with a velocity of 3600 m/s is
9.34*10^5\ m

How to calculate the height the project will reach above the surface?

First, we shall calculate the acceleration due to gravity of the planet. Details below:

  • Radius of planet (r) =
    5.0*10^(6)\ m
  • Mass of planet (M) =
    2.6*10^(24)\ Kg
  • Gravitational constant (G) =
    6.67*10^(-11)\ Nm^(2)/Kg^(2)
  • Acceleration due to gravity of planet (g) = ?


g = (GM)/(r^2) \\\\ g = (6.67*10^(-11)\ *\ 2.6*10^(24))/((5.0*10^(6))^(2)) \\\\g = 6.94\ m/s^2

Finally, we shall calculate the height reach by the projectile above the surface. This is shown below:

  • Initial velocity of projectile (u) = 3600 m/s
  • Acceleration due to gravity of planet (g) = 6.94 m/s²
  • Maximum height (h) =?


h = (u^2)/(2g) \\\\h = (3600^2)/(2\ *\ 6.94)\\\\h = 9.34*10^5\ m

Complete question:

A huge cannon is assembled on an airless planet. The planet has a radius of 5.0×106m and a mass of 2.6×1024kg . The cannon fires a projectile straight up at 3600 m/s. What height does the projectile reach above the surface?

User Carlos Rojas
by
7.7k points