Question

Saige's spaceship traveled \[588\] kilometers \[(\text{km})\] in \[60\] seconds \[(\text{s})\]. Determine whether or not each spaceship trip below has the same speed as Saige's spaceship. Has the same speed as Saige's spaceship Does not have the same speed as Saige's spaceship \[441\,\text{km}\] in \[45\,\text{s}\] \[215\,\text{km}\] in \[25\,\text{s}\] \[649\,\text{km}\] in \[110\,\text{s}\]

Answer 1

After calculating the speed of each trip, only the first trip of 441 km in 45 s has the same speed as Saige's spaceship (9.8 km/s). The other two trips do not have the same speed.

Step-by-step explanation:

The student's question involves determining if the speed is the same for different trips of Saige's spaceship when given the distance and time. To find the speed, we use the formula:

Speed = Distance / Time

We can then compare the calculated speed for each trip to Saige's speed of 588 km in 60 s, which is 9.8 km/s.

For the first trip of 441 km in 45 s, the speed is:

Speed = 441 km / 45 s = 9.8 km/s.

For the second trip of 215 km in 25 s, the speed is:

Speed = 215 km / 25 s = 8.6 km/s, which does not have the same speed as Saige's spaceship.

For the third trip of 649 km in 110 s, the speed is:

Speed = 649 km / 110 s = 5.9 km/s, which also does not have the same speed as Saige's spaceship.

Therefore, only the first trip has the same speed as Saige's spaceship.