Question

A lift motor has to move a fully laden lift 5.18 m between floor 1 and floor 2. The lift has a mass of 2150kg and takes 9.16 s to move from floor 1 to floor 2 (ignore friction). What is the power of the lift in watts during this time? (Assume that acceleration due to gravity is 9.81 m/s2; round your answer to two decimal places; DO NOT include units)

Answer 1

To calculate the power of the lift motor, use the formula P = (mass × gravity × height) / Time. With the lift's mass as 2150 kg, height moved as 5.18 m, and time taken as 9.16 s, the power is 12956.16 watts after rounding to two decimal places.

Step-by-step explanation:

To find the power of a lift motor that moves a fully laden lift, we can use the formula for power, which is the work done divided by time.

Work done is equal to the force exerted on the lift (which is its weight, due to gravity) times the distance moved. The formula for power P will thus be:

P = (Force × Distance) / Time
= (mass × gravity × height) / Time

Plugging in the given values:

P = (2150 kg × 9.81 m/s² × 5.18 m) / 9.16 s
= (21059.5 kg·m²/s² × 5.18 m) / 9.16 s
= 118725.87 kg·m²/s³ / 9.16 s
= 12956.16 W

After rounding to two decimal places, the power of the lift during this time is 12956.16 watts.