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What is the result of d(Arctan(x)/dx)?

A) ¹∕₍₁₊ₓ²₎
B) ¹/ₐ₍₁₊(ˣ∕ₐ)²₎
C) ᵃ∕₍ₐ²₊ₓ²₎
D) Arctan(x) + C

User Leymannx
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1 Answer

4 votes

Final answer:

The result of
d(Arctan(x)/dx) is 1/(1+x^2).

Step-by-step explanation:

The derivative of
Arctan(x) with respect to x, denoted as
d(Arctan(x))/dx, can be found using the chain rule.


Let y = Arctan(x).

The chain rule states that
d(Arctan(x))/dx = dy/dx = dy/dt * dt/dx.In this case,
dt/dx = 1, since
t = x. The derivative of
Arctan(t) with respect to
t, dy/dt, can be found using the derivative of inverse trigonometric functions.

The derivative o
f Arctan(t) is 1/(1+t^2).

Therefore,
d(Arctan(x))/dx = 1/(1+x^2).

User Incepter
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