f(0) = -2, f(-3) = -5, f(2) = 2 (using limit) as the function is undefined at 2.
Here are the values of f(0), f(-3), and f(2) for the given function:
f(0) = -2
Substitute t = 0 into the function:
f(0) = (0)(0-3)/(0-2) + (4-0)/(0-2) = -3/-2 + 4/-2 = -2
f(-3) = -5
Substitute t = -3 into the function:
f(-3) = (-3)(-3-3)/(-3-2) + (4-(-3))/(-3-2) = 18/-5 + 7/-5 = -5
f(2) = 2 (using the limit as t approaches 2)
The function is undefined at t = 2 due to division by zero. However, we can find the limit as t approaches 2 to determine the value:
lim(t→2) f(t) = lim(t→2) [t(t-3)/(t-2) + (4-t)/(t-2)]
This limit evaluates to 2 using L'Hôpital's rule or by simplifying the expression.
Therefore, f(0) = -2, f(-3) = -5, and f(2) = 2 (using the limit).