75.7k views
2 votes
Find the zeros of the function. Enter the solutions from least to greatest. h(x)=-5x^2 +180

User Athan
by
6.2k points

1 Answer

5 votes

Final answer:

To find the zeros of the function h(x) = -5x^2 + 180, we need to solve the equation -5x^2 + 180 = 0. The zeros of the function are x = 6 and x = -6.

Step-by-step explanation:

To find the zeros of the function h(x) = -5x^2 + 180, we need to solve the equation -5x^2 + 180 = 0.

Let's set the equation equal to zero and solve for x:

-5x^2 + 180 = 0

Now, divide both sides of the equation by -5 to get:

x^2 - 36 = 0

Next, we can factor the equation as (x - 6)(x + 6) = 0.

Setting each factor equal to zero, we get:

x - 6 = 0 or x + 6 = 0

Solving for x in each equation, we find the zeros to be x = 6 and x = -6.

User Tspore
by
7.8k points