Question

Sedation ordered for a 13-lb (5.91 kg) cat at 11 mg/kg is supplied as a liquid with a concentration of 100 mg/mL. What volume is needed for this patient?

A. 0.65 mL
B. 0.88 mL
C. 1.25 mL
D. 1.43 mL

Answer 1

To determine the volume of sedation needed for a 13-lb cat at an 11 mg/kg dose and a concentration of 100 mg/mL, multiply the cat's weight by the dosage to get the total mg needed, then divide by the concentration. The calculated volume is 0.65 mL.

Step-by-step explanation:

The subject of the question involves Mathematics, particularly focused on the calculation of dosages in a veterinary medicine context. To calculate the volume of sedation needed for a 13-lb (5.91 kg) cat at a dose of 11 mg/kg with a concentration of 100 mg/mL, we will use the following steps:

• First, calculate the total dosage by multiplying the weight of the cat by the dosage per kilogram: 5.91 kg x 11 mg/kg = 65.01 mg.
• Next, determine the volume of the medication needed by dividing the total dosage by the concentration of the medication: 65.01 mg ÷ 100 mg/mL = 0.6501 mL.
• Finally, round the answer to the nearest reasonable measurement considering the calibration of dosing equipment, which is often to the nearest hundredth of a milliliter: 0.6501 mL is rounded to 0.65 mL.

Therefore, the volume of sedation required for the patient is 0.65 mL (Answer A).