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What is the molarity of a 400mL containing 101.6g of MgCl2 6H2O

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Final answer:

The molarity of the solution is 1.25 M.

Step-by-step explanation:

To find the molarity of a solution, we need to use the formula: Molarity (M) = moles of solute / liters of solution. First, we need to find the moles of MgCl2 ·6H2O.

The molar mass of MgCl2 ·6H2O is 203.31 g/mol.

So, we can calculate the moles of MgCl2 ·6H2O by dividing the given mass by the molar mass: 101.6g / 203.31 g/mol = 0.5 mol.

Next, we need to convert the volume of the solution from milliliters to liters. There are 1000 mL in 1 L, so 400 mL is equal to 400/1000 = 0.4 L.

Now, we can plug in the values into the formula: Molarity (M) = 0.5 mol / 0.4 L

= 1.25 M.

User Ramzi SAYAGH
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