Question

What is the value of x after the following statements execute?

int x = 5;
int y = 30;
do
x = x * 2;
while (x < y);

Answer 1

The value of x after the execution of the do-while loop is 40. The loop doubles the value of x from its initial 5 until it becomes greater than y, which is 30, resulting in three iterations.

Step-by-step explanation:

The question is asking for the value of x after the execution of a do-while loop in programming. The initial value of x is set to 5, and it is doubled each time the loop runs (x = x * 2), as long as the condition (x < y) holds true, where y is 30. The loop terminates once x reaches a value that is not less than y.

Let's go through the iterations:

1. x starts at 5.
2. After first loop, x is 5 * 2 = 10.
3. After second loop, x is 10 * 2 = 20.
4. After third loop, x is 20 * 2 = 40.

After the third loop, x becomes 40, which is greater than y (30). The do-while loop then terminates. Thus, the value of x after the loop execution is 40.