Question

Assume all variables are properly declared. What is the output of the following C++ code?

n = 1;
while (n < 5)
{
n++;
cout << n << " ";
}

Answer 1

The output of the given C++ code is 2 3 4 5. The code uses a while loop to increment the value of a variable and print it until it reaches 5.

Step-by-step explanation:

The output of the given C++ code is 2 3 4 5. Here's how it works:

1. The variable 'n' is initialized to 1.
2. The while loop checks if 'n' is less than 5. Since 1 is less than 5, the loop is entered.
3. The value of 'n' is incremented by 1 using the '++' operator, making it 2.
4. The value of 'n' is printed, followed by a space, using the 'cout' statement. So, 2 is printed.
5. The loop repeats for the next iteration. 'n' is incremented to 3 and printed. This process continues until 'n' becomes 5.

Therefore, the output of the code is: 2 3 4 5.