Question

What is the output of the following C++ code?

count = 1;
num = 25;
while (count < 25)
{
num = num - 1;
count++;
}
cout << count << " " << num << endl;

Answer 1

The output of the provided C++ code, which includes a while loop for decrementing a num variable, will be "25 1" after the loop completes.

Step-by-step explanation:

The output of the given C++ code can be determined by understanding how a while loop works. The code snippet is a C++ program segment that uses a while loop to decrement the value of num until the value of count reaches 24. Initially, num is set to 25 and count is set to 1. Inside the loop, for each iteration, num is decremented by 1, and count is incremented by 1. The loop runs as long as the value of count is less than 25.

When count reaches 25, the condition of the loop (count < 25) becomes false, and the loop stops executing. At this point, num would have been decremented 24 times (from 25 down to 1) because the loop started when count was 1 and stopped when it reached 25. Therefore, the final output printed to the screen will be the current values of count and num, which will be "25 1".