Question

Two resistors are connected in series to a power source. The voltage drop across the first resistor is 5.40 V and the voltage drop across the second resistor is 9.80 V. The current through the circuit is 1.20 A. What is the resistance of each of the resistors?

Option 1: 4.5 Ω, 8.17 Ω
Option 2: 3.6 Ω, 8.17 Ω
Option 3: 4.5 Ω, 6.5 Ω
Option 4: 3.6 Ω, 6.5 Ω

Answer 1

To find the resistance of each resistor, apply Ohm's law (V = IR). The first resistor has a resistance of 4.5 Ω and the second one has 8.17 Ω. The correct answer is Option 1.

Step-by-step explanation:

The question is asking us to calculate the resistance of two resistors connected in series given the voltage drop across each and the current through the circuit. According to Ohm's law, V = IR, where V is the voltage drop, I is the current, and R is the resistance.

For the first resistor, we have a voltage drop of 5.40 V and current of 1.20 A. Hence, the resistance R1 is:

R1 = V / I = 5.40 V / 1.20 A = 4.5 Ω

For the second resistor, we have a voltage drop of 9.80 V and the same current of 1.20 A. Hence, the resistance R2 is:

R2 = V / I = 9.80 V / 1.20 A = 8.17 Ω

The correct answer is Option 1: 4.5 Ω for the first resistor and 8.17 Ω for the second resistor.