Question

Three 12.0-Ω resistors are connected in series to a 50.0-V power source.

What is the equivalent resistance of the circuit?

Option 1: 36.0 Ω
Option 2: 24.0 Ω
Option 3: 50.0 Ω
Option 4: 12.0 Ω

Answer 1

The equivalent resistance for three 12.0-Ω resistors connected in series is 36.0 Ω, which is obtained by adding the resistance values together.

Step-by-step explanation:

The question seeks to determine the equivalent resistance of three 12.0-Ω resistors when connected in series to a 50.0-V power source. When resistors are connected in series, their resistances simply add up to give the total resistance. Since we have three resistors each of 12.0 Ω, we calculate the equivalent resistance as:

Req = R1 + R2 + R3 = 12.0 Ω + 12.0 Ω + 12.0 Ω = 36.0 Ω

Therefore, the correct answer is Option 1: 36.0 Ω, which represents the equivalent resistance of the circuit.