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Question

Given: ABCD is a rectangle and
FA is congruent GD.
Prove: EB is congruent to EC.

User Jax
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1 Answer

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In a rectangle where opposite sides are congruent and diagonals intersect at a point G, segments connecting the point G to opposite vertices (EB and EC) are also congruent.

1. Properties of Rectangles:

Opposite sides are congruent (AB ≅ CD)

Diagonals bisect each other (AG ≅ BG and CG ≅ DG)

2. Triangle Similarity:

Triangles ABG and CDG share two pairs of congruent sides (AB ≅ CD and AG ≅ CG) and have a common included angle (∠AGB ≅ ∠CDG, right angles due to rectangle definition).

By AA Similarity, triangles ABG and CDG are similar.

3. Corresponding Side Congruence:

Since triangles ABG and CDG are similar, corresponding sides have equal ratios.

Specifically, EB/EC = AG/CG = 1 (as AG ≅ CG due to diagonal bisection).

Therefore, EB ≅ EC (multiplying both sides by EC).

Therefore, in rectangle ABCD with diagonals intersecting at G and FA ≅ GD, EB is congruent to EC.

User Muratso
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