Question

What is the output of the following code:

ArrayList list = new ArrayList();
Date d = new Date();
list.add(d);
list.add(d);
System.out.println((list.get(0) == list.get(1)) + " " + (list.get(0)).equals(list.get(1)));


A. true false
B. false true
C. true true
D. false false

Answer 1

The output of the code is true true, since the same Date object is added to the ArrayList twice, resulting in both == and .equals() comparisons returning true.

Step-by-step explanation:

The code creates an ArrayList and adds the same Date object to it twice. When using the == operator, it compares the memory addresses of the objects, and since it's the same object added twice, it will return true. The .equals() method for a Date object compares the values, and since both elements in the list refer to the same object and hence the same value, this comparison also returns true. Therefore, the output of the code will be true true.