Question

What is the output of the following code:

public class Test {
public static void main(String[] args) {
String s1 = new String("Java");
String s2 = new String("Java");
System.out.println((s1 == s2) + " " + (s2));
}
}


A. false false
B. true true
C. false true
D. true false

Answer 1

The output of the provided Java code is 'false true'. The '==' operator checks if two references point to the same object, which is false, and the reference 's2' points to a String object containing 'Java'.

Step-by-step explanation:

The student's code is asking what the output of a small Java program will be. The program declares two String objects, s1 and s2, and initializes them with the same string value "Java". However, since new String() is used to create both strings, they are distinct objects in memory.

The line System.out.println((s1 == s2) + " " + (s2)); uses == to compare the two references, which will false because they point to different objects. The s2 variable is then converted to a string by System.out.println() which results in the string "Java" being printed. Therefore, the output of the code will be false true.