Question

A collection of coins consists of nickels, dimes and quarters. There are three fewer quarters than nickels and six more dimes than quarters. How many of each kind of coin are in the collection if the total value of the collection is $4.35

Answer 1

There are 12 nickels, 9 quarters, and 15 dimes.

I hope this turns out useful for you!

Explanation:

Reading the problem repeatedly, I found that the nickels were the value that I could change to find out the values of the other coins and to find the answer. I started with the number of nickels as 20, calculating 20 x 5 (5 as the value of the nickel) = 100 ($1.00). Then, I subtracted three from 20 since the number of quarters was 3 less and got 17. 17 x 25 = a value far too big when we were going to add dimes as well, so 8 lowered the number of nickels a reasonable amount and tried again, following the directions in the problem. It took a bit, but I found a value that worked.

Nickel = $0.05

Quarter = $0.25

Dime = $0.10

My work (though I converted a bit using my sense of money)

12 x 5 = $0.60

12 - 3 = 9

9 x 25 = $2.25

9 + 6 = 15

15 x 10 = $1.50

$0.60 + $2.25 + $1.50 = $4.35