Question

A table of values is shown.

Show work

Answer 1

This is my method.

Take two points.

(X₁ = -8, Y₁ = 8)

(X₂ = -3, Y₂ = 4.875 or 4 7/8)

Equation of a straight line:

y = mx + b ------(i)

Step 1: Calculating Slope (m).

`(y_2-y_1)/(x_2-x_1 )`

`(4.875-8)/(-3--8)`

`(-3.12500)/(5)`

`m=-0.625`

Now putting value of m in equation (i)

y = -0.625x + b -----(ii)

Step 2: Calculating Y-intercept (b).

Lets choose the first point, (-8,8) for calculating y-intercept:

y = mx + b

8 = -0.625(-8) + b

8 = 5 + b

3 = b

b = 3

Now putting value of b in equation (ii)

y = -0.625x + 3

This is slope-intercept form, now let's convert to point-slope formula.

⇒
`y-2.375=-0.625(x-1)`