Final answer:
In 1000 mL of a solution containing 5% dextrose and 0.45% normal saline, there would be 50 grams of dextrose and 4.5 grams of NaCl.
Step-by-step explanation:
The question asks to calculate the amount of dextrose and sodium chloride (NaCl) in 1000 mL of a 5% dextrose and 0.45% normal saline solution. To find the mass of each component, we use the percentages to calculate what 5% and 0.45% of 1000 mL would be in grams.
To calculate the mass of dextrose: 5% of 1000 mL is 5/100 × 1000 mL = 50 grams.
To calculate the mass of sodium chloride: 0.45% of 1000 mL is 0.45/100 × 1000 mL = 4.5 grams.
Therefore, the correct answer is b) 50 grams of dextrose, 4.5 grams of NaCl.