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Calculate the amount of dextrose and sodium chloride (NaCl) in 1000 mL of 5% dextrose and 0.45% normal saline (D5 and 1/2 NS).

a) 45 grams of dextrose, 0.45 grams of NaCl
b) 50 grams of dextrose, 4.5 grams of NaCl
c) 500 grams of dextrose, 45 grams of NaCl
d) 5 grams of dextrose, 0.045 grams of NaCl

User Lomec
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1 Answer

2 votes

Final answer:

In 1000 mL of a solution containing 5% dextrose and 0.45% normal saline, there would be 50 grams of dextrose and 4.5 grams of NaCl.

Step-by-step explanation:

The question asks to calculate the amount of dextrose and sodium chloride (NaCl) in 1000 mL of a 5% dextrose and 0.45% normal saline solution. To find the mass of each component, we use the percentages to calculate what 5% and 0.45% of 1000 mL would be in grams.

To calculate the mass of dextrose: 5% of 1000 mL is 5/100 × 1000 mL = 50 grams.

To calculate the mass of sodium chloride: 0.45% of 1000 mL is 0.45/100 × 1000 mL = 4.5 grams.

Therefore, the correct answer is b) 50 grams of dextrose, 4.5 grams of NaCl.

User WillD
by
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