Question

Consider the following set of processes, the length of the CPU burst time given in milliseconds :

Process Burst time
P1 6
P2 8
P3 7
P4 3
Assuming the above process being scheduled with the SJF scheduling algorithm :
a) The waiting time for process P4 is 3ms.
b) The waiting time for process P4 is 0ms.
c) The waiting time for process P4 is 16ms.
d) The waiting time for process P4 is 9ms.

Answer 1

The waiting time for process P4 using the Shortest Job First (SJF) scheduling algorithm is 0 milliseconds because it has the shortest burst time among the given processes and is therefore scheduled first.

Step-by-step explanation:

SJF Scheduling Algorithm Example

To determine the waiting time for process P4 using the Shortest Job First (SJF) scheduling algorithm, we need to understand that SJF selects the process with the shortest burst time to execute next. We have the following processes and burst times:

• P1: 6ms
• P2: 8ms
• P3: 7ms
• P4: 3ms

In the given scenario, since P4 has the shortest burst time, it will be scheduled first. Hence, the waiting time for process P4 is 0 milliseconds because it is the first to execute. Other processes would have to wait for P4 to finish before they get their turn. Therefore, the correct answer to the question is option (b), which states that the waiting time for process P4 is 0ms.