Final answer:
Displacement reactions of halide ions with silver nitrate in aqueous solutions result in the formation of precipitates. Options 2, 3, and 4 describe correct displacement reactions leading to the formation of silver bromide, silver chloride, and silver chloride precipitates respectively.
Step-by-step explanation:
The displacement reactions of halide ions in aqueous solutions involve the reaction of halide salts with silver nitrate to form a precipitate. These reactions are outlined below:
- When chlorine (Cl2) is added to sodium iodide (NaI), a brown coloration is observed, corresponding to the formation of iodine (I2), which means that the equation 2NaI + Cl2 -> 2NaCl + I2 does indeed describe a displacement reaction where chlorine displaces iodide ions.
- When silver nitrate (AgNO3) solution is added to various solutions of halide salts like potassium bromide (KBr), potassium chloride (KCl), or sodium chloride (NaCl), a precipitation reaction occurs. Silver chloride (AgCl) is a white precipitate, silver bromide (AgBr) is cream-colored, and silver iodide (AgI) is yellow.
In summary, the reactions provided as Option 2, Option 3, and Option 4 all correctly describe the displacement reactions, producing precipitates of AgBr, AgCl, and AgCl respectively, with their corresponding soluble nitrates remaining in solution.