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What are the oxidation states of the constituent elements in Sulfuric acid?

Option 1: Sulfur (+6), Oxygen (-2), Hydrogen (+1)
Option 2: Sulfur (+4), Oxygen (-2), Hydrogen (+1)
Option 3: Sulfur (-2), Oxygen (-1), Hydrogen (+1)
Option 4: Sulfur (+2), Oxygen (-2), Hydrogen (+1)

User Youeye
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1 Answer

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Final answer:

The oxidation states in sulfuric acid are 1) Sulfur (+6), Oxygen (-2), Hydrogen (+1). This is because oxygen typically has an oxidation state of -2 and hydrogen +1, so sulfur must be +6 to balance the overall charge of the molecule.

Step-by-step explanation:

The oxidation states of the constituent elements in sulfuric acid (H₂SO₄) can be determined using the rules for assigning oxidation numbers.

First, we know that hydrogen generally has an oxidation state of +1, and oxygen has a typical oxidation state of -2. The molecule has two hydrogen atoms, each contributing +1, for a total of +2 from hydrogen. The molecule has four oxygen atoms, each contributing -2, for a total of -8 from oxygen.

Since the charge of a molecule is neutral, the oxidation state of sulfur must offset the contributions of hydrogen and oxygen, which means sulfur must have an oxidation state of +6 to balance the -8 from oxygen and +2 from hydrogen.

This gives us a total of +6 + (-8) + (+2) = 0, which is consistent with the fact that sulfuric acid is a neutral molecule.

User Algiecas
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