Question

-8y² - 1 = -8y

Quadratic equation

Answer 1

y = (2 + √2)/4 ; y = (2 - √2)/4

Explanation:

-8y² + 8y - 1 = 0

8y² - 8y + 1 = 0

discriminant = 64 - 4(8) = 64 - 32 = 32 = 2^4 * 2

y = (8 +
`√(2^4 * 2)`)/16

(8 + 2²√2)/16

(8 + 4 √2) / 16

4(2+√2)/16

(2+√2)/4

y = (8 -
`√(2^4 * 2)`)/16

(8 - 4√2) / 16

4(2-√2)/16

(2-√2)/4