Final answer:
Lithium (Li) has a larger atomic radius than Fluorine (F) due to its position on the periodic table. Rb (rubidium) has the largest atomic radius when compared to Li, N, F, and I. Oxygen (O) has the highest first ionization energy compared to Mg, Ba, B, and Te.
Step-by-step explanation:
When comparing atomic radii of lithium (Li) and fluorine (F), Lithium (Li) has the larger atomic radius. Atomic radius tends to increase as one moves down a group in the periodic table due to the addition of energy levels. Since lithium is located in the second period, while fluorine is in the same period but further to the right, lithium has fewer protons in its nucleus causing less pull on its electron cloud. This means that lithium's electrons can spread out more than those in fluorine, resulting in a larger atomic radius for lithium.
To compare multiple elements such as Li, Rb, N, F, and I, Rb (rubidium) has the largest atomic radius because it is located further down a group in the periodic table. Conversely, examining first ionization energy which increases across a period and up a group, oxygen (O) would have the largest first ionization energy among Mg, Ba, B, O, and Te due to its high electronegativity and stable electron configuration.