Question

Balance the following chemical equations k3po4 bacl2

Answer 1

The balanced chemical equation is
`\(2K_3PO_4 + 3BaCl_2 \rightarrow 6KCl + 2Ba_3(PO_4)_2\).`

To balance the chemical equation
`\(K_3PO_4 + BaCl_2 \rightarrow KCl + Ba_3(PO_4)_2\)`, you can follow these steps:

1. Write down the unbalanced equation:

`\(K_3PO_4 + BaCl_2 \rightarrow KCl + Ba_3(PO_4)_2\)`

2. Count the number of atoms of each element on both sides of the equation.

3. Start by balancing the metals. In this case, balance barium (Ba) first by placing a coefficient of 3 in front of
`\(BaCl_2\)`:

`\(K_3PO_4 + 3BaCl_2 \rightarrow KCl + Ba_3(PO_4)_2\)`

4. Now, balance the chlorine (Cl) atoms. Add a coefficient of 6 in front of
`\(KCl\)` to balance the chlorine atoms on the right side:

`\(K_3PO_4 + 3BaCl_2 \rightarrow 6KCl + Ba_3(PO_4)_2\)`

5. Balance the potassium (K) atoms by placing a coefficient of 2 in front of
`\(K_3PO_4\)`:

`\(2K_3PO_4 + 3BaCl_2 \rightarrow 6KCl + Ba_3(PO_4)_2\)`

6. Finally, balance the phosphorus (P) and oxygen (O) atoms by placing a coefficient of 2 in front of
`\(Ba_3(PO_4)_2\)`:

`\(2K_3PO_4 + 3BaCl_2 \rightarrow 6KCl + 2Ba_3(PO_4)_2\)`

The balanced chemical equation is
`\(2K_3PO_4 + 3BaCl_2 \rightarrow 6KCl + 2Ba_3(PO_4)_2\).`

The probable question could be Balance the following chemical equation
`\(K_3PO_4 + BaCl_2 \rightarrow KCl + Ba_3(PO_4)_2\)`