Question

How many moles of sodium chloride will be produced if we used 1 mole of sodium hydroxide and 0.25 moles of hydrochloric acid? Calculate the mass of sodium chloride produced.

NaOH + HCl -> NaCl + H_2O
A) 0.25 moles, 18g
B) 0.25 moles, 36g
C) 1 mole, 18g
D) 1 mole, 36g

Answer 1

The correct answer is 0.25 moles of NaCl will be produced. To find the mass of NaCl produced, we multiply the number of moles by the molar mass of NaCl. However, none of the provided options accurately represent the correct mass of NaCl which should be 14.61 g.

The correct option is B.

Step-by-step explanation:

To determine how many moles of sodium chloride (NaCl) will be produced when reacting 1 mole of sodium hydroxide (NaOH) with 0.25 moles of hydrochloric acid (HCl), we must look at the stoichiometry of the balanced chemical equation:

NaOH + HCl → NaCl + H_2O

This reaction shows a one-to-one mole ratio between NaOH and HCl. Since we only have 0.25 moles of HCl, it will be the limiting reagent, and thus only 0.25 moles of NaCl can be formed.

To calculate the mass of sodium chloride produced, we use its molar mass (58.44 g/mol):

0.25 moles × 58.44 g/mol = 14.61 g

None of the provided options accurately reflect the correct mass. Therefore, we can conclude there is an error in the options given. If we had to choose the closest option in terms of moles, it would be:

Option B) 0.25 moles, 36g