Question

How many moles of copper will be produced if we used 0.5 moles of copper sulfate and 1 mole of magnesium? Calculate the mass of copper produced.

CuSO_4 + Mg -> MgSO_4 + Cu
A) 0.25 moles, 32g
B) 0.5 moles, 32g
C) 0.5 moles, 64g
D) 1 mole, 32g

Answer 1

To calculate the number of moles of copper produced in the reaction, we can use the balanced chemical equation and the given amounts of copper sulfate and magnesium. The correct answer is option B) 0.5 moles, 32g.

Step-by-step explanation:

To calculate the number of moles of copper produced in the reaction, we can use the balanced chemical equation and the given amounts of copper sulfate and magnesium. The balanced chemical equation is CuSO₄ + Mg -> MgSO₄ + Cu. According to the equation, one mole of copper sulfate reacts with one mole of magnesium to produce one mole of copper. Therefore, if we start with 0.5 moles of copper sulfate, we will produce 0.5 moles of copper.

To calculate the mass of copper produced, we need to know the molar mass of copper (Cu). The molar mass of copper is 63.55 g/mol. So, if we produce 0.5 moles of copper, the mass of copper produced is 0.5 moles x 63.55 g/mol = 31.78 g.

The correct answer is option B) 0.5 moles, 32g.