Question

An electromagnet produces a magnetic field of 0.5 T in a cylindrical region of radius 2.0 cm between its poles. A straight wire carrying a current of 10 A passes through

Answer 1

The magnetic field exerts a force of
`\( 0.2 \, \text{N} \)` on the wire carrying a current of 10.0 A

How to determine the magnitude of force exert on the wire?

The force exerted on a wire carrying a current in a magnetic field can be calculated using the formula:

`\[ \text{Force} = I * L * B \]`

Given:

Current
`(\( I \)) = 10.0 A`

Magnetic field strength
`(\( B \)) = 0.500 T`

Length of the wire within the magnetic field
`(\( L \)) = 0.04 m` (diameter of the cylindrical region)

By substituting the values into the formula:

`\[ \text{Force} = 10.0 \, \text{A} * 0.04 \, \text{m} * 0.500 \, \text{T} = 0.2 \, \text{N} \]`

Hence, the magnetic field exerts a force of
`\( 0.2 \, \text{N} \)` on the wire carrying a current of 10.0 A.

Complete question:

An electromagnet produces a magnetic field of 0.500 T in a cylindrical region of radius 2.0 cm between its poles. A straight wire carrying a current of 10.0 A passes through the center of this region and is perpendicular to both the axis of the cylindrical region and the magnetic field. What magnitude of force does this field exert on the wire