Question

A bowler rolls a 4.5 kg ball down the lane. The ball hits a 0.25kg bowling pin and accelerates the pin away from it at 6.6 m/s2. What is the acceleration felt by the ball (in m/s2)

Answer 1

Answer: 0.37 m/s2

Step-by-step explanation:

This is a Newton's 3rd Law of Motion problem. The force exerted on the pin by the ball is equal and opposite to the force exerted by the pin on the ball. F = ma

let x = acceleration of the ball after it hits the pin

(4.5 kg)(x) = (0.25 kg)(6.6 m/s2)

x = ((0.25 kg)(6.6 m/s2)) / (4.5 kg) = 1.65 / 4.5 = 0.37 m/s2