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What is the molarity of a solution which contains 14.52 g of KF in 500.0 mL of water

User Keir
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Final answer:

The molarity of the KF solution is 0.50 M.

Step-by-step explanation:

To calculate the molarity of a solution, we need to determine the number of moles of solute (KF) and the volume of the solution (in liters). The formula for molarity is Molarity (M) = moles of solute / volume of solution (in liters).

First, we need to convert the mass of KF to moles. The molar mass of KF is 58.10 g/mol (potassium has a molar mass of 39.10 g/mol and fluorine has a molar mass of 19.00 g/mol).

To convert grams to moles, we use the formula:

moles = mass / molar mass

moles of KF = 14.52 g / 58.10 g/mol = 0.25 mol KF

Next, we convert the volume of the solution from milliliters to liters:

volume of solution (in liters) = 500.0 mL / 1000 mL/L = 0.500 L

Now we can calculate the molarity:

Molarity (M) = moles of solute / volume of solution (in liters) = 0.25 mol / 0.500 L = 0.50 M

User Macpandit
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