Question

A crate is pulled to the right with a force of 71.6 N, to the left with a force of 228.2 N, upward with a force of 457.7 N, and downward with a force of 232 N.

Pt 1: What is the net external force in the x direction? Answer in units of N.
Pt 2: What is the net external force in the y direction? Answer in units of N.
Pt 3: What is the magnitude of the net external force on the crate?
Pt 4: What is the direction of the net external force on the crate (as an angle between −180◦ and 180◦, measured from the positive x-axis with counterclockwise positive)?

Answer 1

Answer: (see answers below)

Step-by-step explanation:

Fnet x = 71.6 - 228.2 = -156.6 N (left)

Fnet y = 457.7 - 232 = 225.7 N (up)

R =
`\sqrt{-156.6^(2) + 225.7^(2) }` =
`√(75464)` = 274.7 N

Angle of R = 180 - (tan-1)
`(225.7)/(156.6)` = 180 - 55.2 = 124.8°