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The specific heat of aluminum is 0.21 J/g°C. How much heat(Q) is released when a 10 g piece of aluminum foil is taken out of the oven and cools from 100°C to 50°C?

A) 21 J
B) 42 J
C) 84 J
D) 168 J

User Mahelia
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1 Answer

3 votes

Final answer:

The heat released when a 10 g piece of aluminum foil cools from 100°C to 50°C is 42 J.

Step-by-step explanation:

To calculate the amount of heat released when a 10 g piece of aluminum foil cools from 100°C to 50°C, we can use the equation Q = mcΔT, where Q is the heat transferred, m is the mass of the aluminum foil, c is the specific heat of aluminum, and ΔT is the change in temperature.

Plugging in the values, we have Q = (10 g)(0.21 J/g°C)(50°C - 100°C).

Simplifying the equation, we get Q = (-500 J), which is equivalent to -0.5 kJ. Since the heat is being released, the answer should be positive, so the correct answer is B) 42 J.

User Silentkratos
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