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A new Youth Activity Center is being built in Ook Valley. The perimeter of the rectangular playing field is 272 yards. The length of the field is 8 yards less than double the width. What

are the dimensions of the playing field?

User Happyhuman
by
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1 Answer

4 votes
4 votes

Answer:

w = 48 and l = 88

Explanation:

A new Youth Activity Center is being built in Ook Valley. The perimeter of the rectangular playing field is 272 yards. The length of the field is 8 yards less than double the width. What are the dimensions of the playing field?

P = 2w + 2l

w = w

l = 2w - 8

272 = 2w + 2(2w - 8)

272 = 2w + 4w - 16

272 = 6w - 16

288 = 6w

w = 48

remember that: l = 2w - 8

l = 2w - 8 when w = 48

l = 2(48) - 8

l = 96 - 8

l = 88

CHECK: w = 48 and l = 88

P = 2w + 2l

272 = 2(48) + 2(88)

272 = 96 + 176

272 = 272

so: w = 48 and l = 88

User Cathi
by
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