Question

a fireworks display features a 50 kg firework shot at 35 ms justs before the shell explodes it seperates into two smaller shells each with a mass of 25 kg what is the velocity of each smaller shell after they split ignore air resistance​

Answer 1

When a 50 kg firework split into two shells, each with a mass of 25 kg, the velocity of each smaller shell after they split will be 35 m/s.

Step-by-step explanation:

When a 50 kg firework traveling at 35 m/s splits into two shells, each with a mass of 25 kg, the principle of conservation of momentum can be applied. The initial momentum of the system before the explosion is equal to the sum of the momenta of the two smaller shells after the explosion. Therefore, the total momentum before the explosion is:

• Momentum before explosion = mass of firework x velocity of firework = 50 kg x 35 m/s = 1750 kg m/s

After the explosion, the momentum of each smaller shell will be equal but in opposite directions, therefore:

• Momentum of each smaller shell = Total momentum before explosion / Number of smaller shells = 1750 kg m/s / 2 = 875 kg m/s

So, each smaller shell will have a momentum of 875 kg m/s. Since momentum is mass times velocity, we can rearrange the equation to solve for the velocity of each smaller shell:

• Velocity of each smaller shell = Momentum of each smaller shell / Mass of each smaller shell = 875 kg m/s / 25 kg = 35 m/s

Therefore, each smaller shell will have a velocity of 35 m/s after they split.